What is factor 2x^3-x^2(2i-1)-x(3i+5)+2+2i ?

The solution to factor 2x^3-x^2(2i-1)-x(3i+5)+2+2i is (2x^3+x^2-5x+2)+i(2-2x^2-3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 2x^3-x^2(2i-1)-x(3i+5)+2+2i

factor

2 x^{3} - x^{2} (2 i - 1) - x (3 i + 5) + 2 + 2 i

(2 x^{3} + x^{2} - 5 x + 2) + i (2 - 2 x^{2} - 3 x)

Solution steps

2 x^{3} - x^{2} (2 i - 1) - x (3 i + 5) + 2 + 2 i

Rewrite

2 x^{3} - x^{2} (2 i - 1) - x (3 i + 5) + 2 + 2 i

in standard complex form:

(2 x^{3} + x^{2} - 5 x + 2) + (- 2 x^{2} - 3 x + 2) i

= (2 x^{3} + x^{2} - 5 x + 2) + (- 2 x^{2} - 3 x + 2) i

7 m^{7} n - 28 m n^{3}

\frac{1 ^{2}}{2}

2 x^{2} + 3 x - 27 = 0

\frac{1 0 ^{0} r ^{11} s}{3 ^{2}}

x^{2} - 4 x + 4 \leq 0

What is factor 2x^3-x^2(2i-1)-x(3i+5)+2+2i ?
The solution to factor 2x^3-x^2(2i-1)-x(3i+5)+2+2i is (2x^3+x^2-5x+2)+i(2-2x^2-3x)