What are the solutions to the equation 2x^2+24x+64=0 ?

The solutions to the equation 2x^2+24x+64=0 are x=-4,x=-8

Find the zeros of 2x^2+24x+64=0

The zeros of 2x^2+24x+64=0 are x=-4,x=-8

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2 x^{2} + 24 x + 64 = 0

x = - 4, x = - 8

Solution steps

2 x^{2} + 24 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 2 \cdot 64}{2 \cdot 2}

2 4^{2} - 4 \cdot 2 \cdot 64 = 8

x_{1, 2} = \frac{- 24 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 24 + 8}{2 \cdot 2}, x_{2} = \frac{- 24 - 8}{2 \cdot 2}

x = \frac{- 24 + 8}{2 \cdot 2} : - 4

x = \frac{- 24 - 8}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = - 4, x = - 8

- 12 + 8 x \leq - 44

4 j \leq 8

5 + 6 ∣ 4 x - 1 ∣ < 23

3 a^{2} b^{2} \cdot 9 a^{4} b^{6} \cdot 12 a^{2}

8 c^{2} - 88 c + 242

What are the solutions to the equation 2x^2+24x+64=0 ?
The solutions to the equation 2x^2+24x+64=0 are x=-4,x=-8
Find the zeros of 2x^2+24x+64=0
The zeros of 2x^2+24x+64=0 are x=-4,x=-8