What is ((2y^5)/(3y^2))^3 ?

The solution to ((2y^5)/(3y^2))^3 is (8y^9)/(27)

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simplify ((2y^5)/(3y^2))^3

simplify

(\frac{2 y ^{5}}{3 y ^{2}})^{3}

\frac{8 y ^{9}}{27}

Solution steps

(\frac{2 y ^{5}}{3 y ^{2}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 y ^{5} ) ^{3}}{( 3 y ^{2} ) ^{3}}

Simplify

(2 y^{5})^{3} : 8 y^{15}

= \frac{8 y ^{15}}{( 3 y ^{2} ) ^{3}}

Simplify

(3 y^{2})^{3} : 27 y^{6}

= \frac{8 y ^{15}}{27 y ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{y ^{15}}{y ^{6}} = y^{15 - 6}

= \frac{8 y ^{15 - 6}}{27}

Subtract the numbers:

15 - 6 = 9

= \frac{8 y ^{9}}{27}

16 x^{2} + 24 x + 9 = 0

- \frac{3}{4} x \geq - \frac{11}{12} + \frac{1}{3} x

6 r^{2} - 11 r + 4

12.25

\frac{v}{5} - 4 = \frac{v}{3}