What are the solutions to the equation -x^2+4x+3=0 ?

The solutions to the equation -x^2+4x+3=0 are x=2-sqrt(7),x=2+sqrt(7)

Find the zeros of -x^2+4x+3=0

The zeros of -x^2+4x+3=0 are x=2-sqrt(7),x=2+sqrt(7)

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- x^{2} + 4 x + 3 = 0

x = 2 - 7, x = 2 + 7

Decimal Notation

x = - 0.64575 \dots, x = 4.64575 \dots

Solution steps

- x^{2} + 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 3 = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 7}{2 ( - 1 )}

x = \frac{- 4 + 2 7}{2 ( - 1 )} : 2 - 7

x = \frac{- 4 - 2 7}{2 ( - 1 )} : 2 + 7

The solutions to the quadratic equation are:

x = 2 - 7, x = 2 + 7

\frac{3 x - 15}{5} = 6

0 = 5 (x + 7)

∣ 4 x - 1 ∣ = 8

k^{2} + 10 k + 16

∣ 2 x + 4 ∣ \leq - x + 3

What are the solutions to the equation -x^2+4x+3=0 ?
The solutions to the equation -x^2+4x+3=0 are x=2-sqrt(7),x=2+sqrt(7)
Find the zeros of -x^2+4x+3=0
The zeros of -x^2+4x+3=0 are x=2-sqrt(7),x=2+sqrt(7)