What is (4x-1)/(3x+1)>= 1 ?

The solution to (4x-1)/(3x+1)>= 1 is x = 2

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(4x-1)/(3x+1)>= 1

\frac{4 x - 1}{3 x + 1} \geq 1

x < - \frac{1}{3} or x \geq 2

Interval Notation

(- \infty, - \frac{1}{3}) \cup [2, \infty)

Decimal Notation

x < - 0.33333 \dots or x \geq 2

Solution steps

\frac{4 x - 1}{3 x + 1} \geq 1

Rewrite in standard form

\frac{x - 2}{3 x + 1} \geq 0

Identify the intervals

x < - \frac{1}{3} or x \geq 2

2 x^{2} y - 32 y

n^{2} - 3 n - 10

- x - 1 = - 5

5 - \frac{1}{9} x = \frac{13}{3}

\frac{x}{- 3} > - 2

What is (4x-1)/(3x+1)>= 1 ?
The solution to (4x-1)/(3x+1)>= 1 is x<-1/3 \lor x>= 2