What are the solutions to the equation t^2-5t=0 ?

The solutions to the equation t^2-5t=0 are t=5,t=0

Find the zeros of t^2-5t=0

The zeros of t^2-5t=0 are t=5,t=0

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t^{2} - 5 t = 0

t = 5, t = 0

Solution steps

t^{2} - 5 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

t_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, t_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

t = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

t = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 5, t = 0

4 k^{2} - 6 k - 1 = 0

\frac{- 120}{5}

\frac{2 + 3 i}{5 + 2 i}

\frac{x + 4}{5} = \frac{x - 3}{4}

a^{2} + a^{3} + a^{4}

What are the solutions to the equation t^2-5t=0 ?
The solutions to the equation t^2-5t=0 are t=5,t=0
Find the zeros of t^2-5t=0
The zeros of t^2-5t=0 are t=5,t=0