What are the solutions to the equation x^2-6x+19=0 ?

The solutions to the equation x^2-6x+19=0 are x=3+sqrt(10)i,x=3-sqrt(10)i

Find the zeros of x^2-6x+19=0

The zeros of x^2-6x+19=0 are x=3+sqrt(10)i,x=3-sqrt(10)i

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x^{2} - 6 x + 19 = 0

x = 3 + 10 i, x = 3 - 10 i

Solution steps

x^{2} - 6 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 19 : 210 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 10 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 10 i}{2 \cdot 1} : 3 + 10 i

x = \frac{- ( - 6 ) - 2 10 i}{2 \cdot 1} : 3 - 10 i

The solutions to the quadratic equation are:

x = 3 + 10 i, x = 3 - 10 i

2 (x + 5) = - 8

\frac{8 !}{3 ! 5 !}

2 x^{2} + 15 x + 27

6 x^{2} + 7 x - 10

\frac{12}{x - 1} - \frac{6}{x} \geq 4

What are the solutions to the equation x^2-6x+19=0 ?
The solutions to the equation x^2-6x+19=0 are x=3+sqrt(10)i,x=3-sqrt(10)i
Find the zeros of x^2-6x+19=0
The zeros of x^2-6x+19=0 are x=3+sqrt(10)i,x=3-sqrt(10)i