What are the solutions to the equation 121x^2-176x+64=0 ?

The solutions to the equation 121x^2-176x+64=0 are x= 8/11

Find the zeros of 121x^2-176x+64=0

The zeros of 121x^2-176x+64=0 are x= 8/11

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121 x^{2} - 176 x + 64 = 0

x = \frac{8}{11}

Decimal Notation

x = 0.72727 \dots

Solution steps

121 x^{2} - 176 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 176 ) \pm ( - 176 ) ^{2} - 4 \cdot 121 \cdot 64}{2 \cdot 121}

(- 176)^{2} - 4 \cdot 121 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 176 ) \pm 0}{2 \cdot 121}

x = \frac{- ( - 176 )}{2 \cdot 121}

\frac{- ( - 176 )}{2 \cdot 121} = \frac{8}{11}

x = \frac{8}{11}

The solution to the quadratic equation is:

x = \frac{8}{11}

3 x^{2} + 6 x - 105

230

3 x^{2} + 2 x - 12 = 0

\frac{1}{8} \cdot \frac{1}{8}

(x - 3)^{2} \leq 2 (x - 3)

What are the solutions to the equation 121x^2-176x+64=0 ?
The solutions to the equation 121x^2-176x+64=0 are x= 8/11
Find the zeros of 121x^2-176x+64=0
The zeros of 121x^2-176x+64=0 are x= 8/11