What are the solutions to the equation 4x^2+8x=1 ?

The solutions to the equation 4x^2+8x=1 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2

Find the zeros of 4x^2+8x=1

The zeros of 4x^2+8x=1 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2

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4 x^{2} + 8 x = 1

x = \frac{- 2 + 5}{2}, x = - \frac{2 + 5}{2}

Decimal Notation

x = 0.11803 \dots, x = - 2.11803 \dots

Solution steps

4 x^{2} + 8 x = 1

Move

1

to the left side

4 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 1) = 45

x_{1, 2} = \frac{- 8 \pm 4 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 5}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 5}{2 \cdot 4}

x = \frac{- 8 + 4 5}{2 \cdot 4} : \frac{- 2 + 5}{2}

x = \frac{- 8 - 4 5}{2 \cdot 4} : - \frac{2 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 5}{2}, x = - \frac{2 + 5}{2}

e^{5 x} \cdot e^{5 x}

3 n^{3} - n^{2}

x - 3 = \frac{1}{6} x

\frac{3}{4} - \frac{2}{b}

\frac{2}{5 a} \cdot \frac{6}{7 a ^{2}}

What are the solutions to the equation 4x^2+8x=1 ?
The solutions to the equation 4x^2+8x=1 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2
Find the zeros of 4x^2+8x=1
The zeros of 4x^2+8x=1 are x=(-2+sqrt(5))/2 ,x=-(2+sqrt(5))/2