What are the solutions to the equation 12x-9x^2=-3 ?

The solutions to the equation 12x-9x^2=-3 are x=-(-2+sqrt(7))/3 ,x=(2+sqrt(7))/3

Find the zeros of 12x-9x^2=-3

The zeros of 12x-9x^2=-3 are x=-(-2+sqrt(7))/3 ,x=(2+sqrt(7))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x - 9 x^{2} = - 3

x = - \frac{- 2 + 7}{3}, x = \frac{2 + 7}{3}

Decimal Notation

x = - 0.21525 \dots, x = 1.54858 \dots

Solution steps

12 x - 9 x^{2} = - 3

Move

3

to the left side

12 x - 9 x^{2} + 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 9 x^{2} + 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 9 ) \cdot 3}{2 ( - 9 )}

1 2^{2} - 4 (- 9) \cdot 3 = 67

x_{1, 2} = \frac{- 12 \pm 6 7}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 12 + 6 7}{2 ( - 9 )}, x_{2} = \frac{- 12 - 6 7}{2 ( - 9 )}

x = \frac{- 12 + 6 7}{2 ( - 9 )} : - \frac{- 2 + 7}{3}

x = \frac{- 12 - 6 7}{2 ( - 9 )} : \frac{2 + 7}{3}

The solutions to the quadratic equation are:

x = - \frac{- 2 + 7}{3}, x = \frac{2 + 7}{3}

4 (x - 6) = 12

(\frac{x}{y})^{6}

- \frac{2 ( 1 ) ( 2 )}{( 2 ) ^{2} + 4}

3 = - 2 x - 3

x + 1 + 1 + 6 x > 3 (x - 4) - (x - 4)

What are the solutions to the equation 12x-9x^2=-3 ?
The solutions to the equation 12x-9x^2=-3 are x=-(-2+sqrt(7))/3 ,x=(2+sqrt(7))/3
Find the zeros of 12x-9x^2=-3
The zeros of 12x-9x^2=-3 are x=-(-2+sqrt(7))/3 ,x=(2+sqrt(7))/3