What are the solutions to the equation 7x^2+2x=2 ?

The solutions to the equation 7x^2+2x=2 are x=(-1+sqrt(15))/7 ,x=-(1+sqrt(15))/7

Find the zeros of 7x^2+2x=2

The zeros of 7x^2+2x=2 are x=(-1+sqrt(15))/7 ,x=-(1+sqrt(15))/7

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7 x^{2} + 2 x = 2

x = \frac{- 1 + 15}{7}, x = - \frac{1 + 15}{7}

Decimal Notation

x = 0.41042 \dots, x = - 0.69614 \dots

Solution steps

7 x^{2} + 2 x = 2

Move

2

to the left side

7 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 ( - 2 )}{2 \cdot 7}

2^{2} - 4 \cdot 7 (- 2) = 215

x_{1, 2} = \frac{- 2 \pm 2 15}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 2 + 2 15}{2 \cdot 7}, x_{2} = \frac{- 2 - 2 15}{2 \cdot 7}

x = \frac{- 2 + 2 15}{2 \cdot 7} : \frac{- 1 + 15}{7}

x = \frac{- 2 - 2 15}{2 \cdot 7} : - \frac{1 + 15}{7}

The solutions to the quadratic equation are:

x = \frac{- 1 + 15}{7}, x = - \frac{1 + 15}{7}

2 x^{2} - 8 x + 9 = 0

2 x \leq 10

10 m = 10 - 5 (m - 7)

\frac{3}{4} - \frac{6}{12}

8^{2} + 1 5^{2}

What are the solutions to the equation 7x^2+2x=2 ?
The solutions to the equation 7x^2+2x=2 are x=(-1+sqrt(15))/7 ,x=-(1+sqrt(15))/7
Find the zeros of 7x^2+2x=2
The zeros of 7x^2+2x=2 are x=(-1+sqrt(15))/7 ,x=-(1+sqrt(15))/7