What are the solutions to the equation x^2+16x+65=0 ?

The solutions to the equation x^2+16x+65=0 are x=-8+i,x=-8-i

Find the zeros of x^2+16x+65=0

The zeros of x^2+16x+65=0 are x=-8+i,x=-8-i

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x^{2} + 16 x + 65 = 0

x = - 8 + i, x = - 8 - i

Solution steps

x^{2} + 16 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot 65 : 2 i

x_{1, 2} = \frac{- 16 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 i}{2 \cdot 1}

x = \frac{- 16 + 2 i}{2 \cdot 1} : - 8 + i

x = \frac{- 16 - 2 i}{2 \cdot 1} : - 8 - i

The solutions to the quadratic equation are:

x = - 8 + i, x = - 8 - i

\frac{195 π}{180}

125 w^{3} y - 343 q^{3} y

x^{4} - (3 x - 2)^{2}

x^{3} + 3 x^{2} + 16 x - 20

What are the solutions to the equation x^2+16x+65=0 ?
The solutions to the equation x^2+16x+65=0 are x=-8+i,x=-8-i
Find the zeros of x^2+16x+65=0
The zeros of x^2+16x+65=0 are x=-8+i,x=-8-i