What are the solutions to the equation 11-2h^2=2+h^2 ?

The solutions to the equation 11-2h^2=2+h^2 are h=sqrt(3),h=-sqrt(3)

Find the zeros of 11-2h^2=2+h^2

The zeros of 11-2h^2=2+h^2 are h=sqrt(3),h=-sqrt(3)

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11 - 2 h^{2} = 2 + h^{2}

h = 3, h = - 3

Decimal Notation

h = 1.73205 \dots, h = - 1.73205 \dots

Solution steps

11 - 2 h^{2} = 2 + h^{2}

Move

11

to the right side

- 2 h^{2} = h^{2} - 9

Move

h^{2}

to the left side

- 3 h^{2} = - 9

Divide both sides by

- 3

h^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

h = 3, h = - 3

\frac{q}{4} - 7 < - 8

\frac{( \frac{a}{b} + 1 )}{( \frac{b}{a} - 1 )}

2 x - 8 < 7

2 x - 9 \leq 3 - x

3 lo g_{2} (8) + 4 lo g_{2} (\frac{1}{2}) - lo g_{3} (2)

What are the solutions to the equation 11-2h^2=2+h^2 ?
The solutions to the equation 11-2h^2=2+h^2 are h=sqrt(3),h=-sqrt(3)
Find the zeros of 11-2h^2=2+h^2
The zeros of 11-2h^2=2+h^2 are h=sqrt(3),h=-sqrt(3)