What are the solutions to the equation 49/16+15/2 =d^2 ?

The solutions to the equation 49/16+15/2 =d^2 are d= 13/4 ,d=-13/4

Find the zeros of 49/16+15/2 =d^2

The zeros of 49/16+15/2 =d^2 are d= 13/4 ,d=-13/4

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\frac{49}{16} + \frac{15}{2} = d^{2}

d = \frac{13}{4}, d = - \frac{13}{4}

Decimal Notation

d = 3.25, d = - 3.25

Solution steps

\frac{49}{16} + \frac{15}{2} = d^{2}

Switch sides

d^{2} = \frac{49}{16} + \frac{15}{2}

Simplify

\frac{49}{16} + \frac{15}{2} : \frac{169}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = \frac{169}{16}, d = - \frac{169}{16}

\frac{169}{16} = \frac{13}{4}

- \frac{169}{16} = - \frac{13}{4}

d = \frac{13}{4}, d = - \frac{13}{4}

250

9 x y^{2} + 6 y^{4} - 12 y^{3} z

\frac{3}{( x - 1 ) ( x + 6 )} < 0

- 2 \leq 3 x + 1 \leq 7

3 a^{4} - 3 a^{2}

What are the solutions to the equation 49/16+15/2 =d^2 ?
The solutions to the equation 49/16+15/2 =d^2 are d= 13/4 ,d=-13/4
Find the zeros of 49/16+15/2 =d^2
The zeros of 49/16+15/2 =d^2 are d= 13/4 ,d=-13/4