What is the answer to 2(1+2t)-3(2-t)+2(-3t)=-7 ?

The answer to 2(1+2t)-3(2-t)+2(-3t)=-7 is t=-3

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2(1+2t)-3(2-t)+2(-3t)=-7

2 (1 + 2 t) - 3 (2 - t) + 2 (- 3 t) = - 7

t = - 3

Solution steps

2 (1 + 2 t) - 3 (2 - t) + 2 (- 3 t) = - 7

Remove parentheses:

(- a) = - a

2 (1 + 2 t) - 3 (2 - t) - 2 \cdot 3 t = - 7

Multiply the numbers:

2 \cdot 3 = 6

2 (1 + 2 t) - 3 (2 - t) - 6 t = - 7

Expand

2 (1 + 2 t) - 3 (2 - t) - 6 t : t - 4

t - 4 = - 7

Move

4

to the right side

t = - 3

(b - c)^{3} + (c - a)^{3}

2 x^{2} = 13 x + 7

- 1 \cdot 5

12 n^{2} - 6 n - 24 = 0

\frac{i ^{26} - i}{i - 1}

What is the answer to 2(1+2t)-3(2-t)+2(-3t)=-7 ?
The answer to 2(1+2t)-3(2-t)+2(-3t)=-7 is t=-3
Solve for t: 2(1+2t)-3(2-t)+2(-3t)=-7
The solution is t=-3