What are the solutions to the equation a^2+10a+21=0 ?

The solutions to the equation a^2+10a+21=0 are a=-3,a=-7

Find the zeros of a^2+10a+21=0

The zeros of a^2+10a+21=0 are a=-3,a=-7

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a^{2} + 10 a + 21 = 0

a = - 3, a = - 7

Solution steps

a^{2} + 10 a + 21 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

a_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 10 + 4}{2 \cdot 1}, a_{2} = \frac{- 10 - 4}{2 \cdot 1}

a = \frac{- 10 + 4}{2 \cdot 1} : - 3

a = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

a = - 3, a = - 7

\frac{15 18}{10 10}

\frac{5 2}{2}

- 4.9 x^{2} + 48.6 x + 525 = 0

\frac{n ^{12}}{n ^{4}}

3 (\frac{5}{3})

What are the solutions to the equation a^2+10a+21=0 ?
The solutions to the equation a^2+10a+21=0 are a=-3,a=-7
Find the zeros of a^2+10a+21=0
The zeros of a^2+10a+21=0 are a=-3,a=-7