What is factor 1+14x^2y+49x^4y^2 ?

The solution to factor 1+14x^2y+49x^4y^2 is (7x^2y+1)^2

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factor 1+14x^2y+49x^4y^2

factor

1 + 14 x^{2} y + 49 x^{4} y^{2}

(7 x^{2} y + 1)^{2}

Solution steps

1 + 14 x^{2} y + 49 x^{4} y^{2}

Group by common factors

= 49 x^{4} y^{2} + 14 x^{2} y + 1

Break the expression into groups

= (49 x^{4} y^{2} + 7 x^{2} y) + (7 x^{2} y + 1)

Factor out

7 x^{2} y

from

49 x^{4} y^{2} + 7 x^{2} y : 7 x^{2} y (7 x^{2} y + 1)

= 7 x^{2} y (7 x^{2} y + 1) + (7 x^{2} y + 1)

Factor out common term

(7 x^{2} y + 1) : (7 x^{2} y + 1) (7 x^{2} y + 1)

= (7 x^{2} y + 1) (7 x^{2} y + 1)

Apply exponent rule:

aa = a^{2}

(7 x^{2} y + 1) (7 x^{2} y + 1) = (7 x^{2} y + 1)^{2}

= (7 x^{2} y + 1)^{2}

48 = 10 w - 7 w

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What is factor 1+14x^2y+49x^4y^2 ?
The solution to factor 1+14x^2y+49x^4y^2 is (7x^2y+1)^2