What are the solutions to the equation 0=8x+128-6x^2 ?

The solutions to the equation 0=8x+128-6x^2 are x=-4,x= 16/3

Find the zeros of 0=8x+128-6x^2

The zeros of 0=8x+128-6x^2 are x=-4,x= 16/3

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0 = 8 x + 128 - 6 x^{2}

x = - 4, x = \frac{16}{3}

Decimal Notation

x = - 4, x = 5.33333 \dots

Solution steps

0 = 8 x + 128 - 6 x^{2}

Switch sides

8 x + 128 - 6 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} + 8 x + 128 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 6 ) \cdot 128}{2 ( - 6 )}

8^{2} - 4 (- 6) \cdot 128 = 56

x_{1, 2} = \frac{- 8 \pm 56}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 8 + 56}{2 ( - 6 )}, x_{2} = \frac{- 8 - 56}{2 ( - 6 )}

x = \frac{- 8 + 56}{2 ( - 6 )} : - 4

x = \frac{- 8 - 56}{2 ( - 6 )} : \frac{16}{3}

The solutions to the quadratic equation are:

x = - 4, x = \frac{16}{3}

u^{2} - 49

\frac{6 n ^{3}}{8 n ^{4}}

(\frac{10}{3})^{2}

(3^{\frac{2}{3}} \cdot 5^{\frac{1}{4}})^{6}

π + \frac{3 π}{2}

What are the solutions to the equation 0=8x+128-6x^2 ?
The solutions to the equation 0=8x+128-6x^2 are x=-4,x= 16/3
Find the zeros of 0=8x+128-6x^2
The zeros of 0=8x+128-6x^2 are x=-4,x= 16/3