What are the solutions to the equation -5x^2+20=0 ?

The solutions to the equation -5x^2+20=0 are x=2,x=-2

Find the zeros of -5x^2+20=0

The zeros of -5x^2+20=0 are x=2,x=-2

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- 5 x^{2} + 20 = 0

x = 2, x = - 2

Solution steps

- 5 x^{2} + 20 = 0

Move

20

to the right side

- 5 x^{2} = - 20

Divide both sides by

- 5

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

\frac{9 !}{7 ! 2 !}

5 x^{2} - 10 = 2 x - 7

4108

3 ∣ 4 w - 1 ∣ - 5 = 10

\frac{y ^{2}}{x ^{2}}

What are the solutions to the equation -5x^2+20=0 ?
The solutions to the equation -5x^2+20=0 are x=2,x=-2
Find the zeros of -5x^2+20=0
The zeros of -5x^2+20=0 are x=2,x=-2