What are the solutions to the equation 6v^2+13v-8=-3 ?

The solutions to the equation 6v^2+13v-8=-3 are v= 1/3 ,v=-5/2

Find the zeros of 6v^2+13v-8=-3

The zeros of 6v^2+13v-8=-3 are v= 1/3 ,v=-5/2

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6 v^{2} + 13 v - 8 = - 3

v = \frac{1}{3}, v = - \frac{5}{2}

Decimal Notation

v = 0.33333 \dots, v = - 2.5

Solution steps

6 v^{2} + 13 v - 8 = - 3

Move

3

to the left side

6 v^{2} + 13 v - 5 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

1 3^{2} - 4 \cdot 6 (- 5) = 17

v_{1, 2} = \frac{- 13 \pm 17}{2 \cdot 6}

Separate the solutions

v_{1} = \frac{- 13 + 17}{2 \cdot 6}, v_{2} = \frac{- 13 - 17}{2 \cdot 6}

v = \frac{- 13 + 17}{2 \cdot 6} : \frac{1}{3}

v = \frac{- 13 - 17}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

v = \frac{1}{3}, v = - \frac{5}{2}

- 225

x^{3} y^{2} - 27 y^{2}

x^{2} + 9 = 6 x

1 + 8 n - 7 = 16 + n + 8 - 2

x^{2} \geq 2 x

What are the solutions to the equation 6v^2+13v-8=-3 ?
The solutions to the equation 6v^2+13v-8=-3 are v= 1/3 ,v=-5/2
Find the zeros of 6v^2+13v-8=-3
The zeros of 6v^2+13v-8=-3 are v= 1/3 ,v=-5/2