What is ((-3b^4)^2)/(-12b^{-9)} ?

The solution to ((-3b^4)^2)/(-12b^{-9)} is -(3b^{17})/4

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simplify ((-3b^4)^2)/(-12b^{-9)}

simplify

\frac{( - 3 b ^{4} ) ^{2}}{- 12 b ^{- 9}}

- \frac{3 b ^{17}}{4}

Solution steps

\frac{( - 3 b ^{4} ) ^{2}}{- 12 b ^{- 9}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3 b^{4})^{2} = (3 b^{4})^{2}

= \frac{( 3 b ^{4} ) ^{2}}{- 12 b ^{- 9}}

Simplify

(3 b^{4})^{2} : 3^{2} b^{8}

= \frac{3 ^{2} b ^{8}}{- 12 b ^{- 9}}

Factor the number:

12 = 3 \cdot 4

= \frac{3 ^{2} b ^{8}}{- 3 \cdot 4 b ^{- 9}}

\frac{3 ^{2}}{3} = 3

= \frac{3 b ^{8}}{- 4 b ^{- 9}}

Simplify

\frac{b ^{8}}{b ^{- 9}} : b^{17}

= \frac{3 b ^{17}}{- 4}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{3 b ^{17}}{4}

v^{2} - 9 = 0

5 x^{2} + 1 = 4 x

s^{2} + 3 s - 40

32 + 4

- 12 \leq t + 7

What is ((-3b^4)^2)/(-12b^{-9)} ?
The solution to ((-3b^4)^2)/(-12b^{-9)} is -(3b^{17})/4