What are the solutions to the equation 18x^2-9x-1=0 ?

The solutions to the equation 18x^2-9x-1=0 are x=(3+sqrt(17))/(12),x=(3-sqrt(17))/(12)

Find the zeros of 18x^2-9x-1=0

The zeros of 18x^2-9x-1=0 are x=(3+sqrt(17))/(12),x=(3-sqrt(17))/(12)

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18 x^{2} - 9 x - 1 = 0

x = \frac{3 + 17}{12}, x = \frac{3 - 17}{12}

Decimal Notation

x = 0.59359 \dots, x = - 0.09359 \dots

Solution steps

18 x^{2} - 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 18 ( - 1 )}{2 \cdot 18}

(- 9)^{2} - 4 \cdot 18 (- 1) = 317

x_{1, 2} = \frac{- ( - 9 ) \pm 3 17}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 17}{2 \cdot 18}, x_{2} = \frac{- ( - 9 ) - 3 17}{2 \cdot 18}

x = \frac{- ( - 9 ) + 3 17}{2 \cdot 18} : \frac{3 + 17}{12}

x = \frac{- ( - 9 ) - 3 17}{2 \cdot 18} : \frac{3 - 17}{12}

The solutions to the quadratic equation are:

x = \frac{3 + 17}{12}, x = \frac{3 - 17}{12}

20 a^{4} b - 20 a^{3} b + 5 a^{2} b

(\frac{2}{2})^{3}

5 x^{2} + 3 x + 2 = 0

24 x - 56 y + 72

15 (x - 3) - 14 x \geq 14

What are the solutions to the equation 18x^2-9x-1=0 ?
The solutions to the equation 18x^2-9x-1=0 are x=(3+sqrt(17))/(12),x=(3-sqrt(17))/(12)
Find the zeros of 18x^2-9x-1=0
The zeros of 18x^2-9x-1=0 are x=(3+sqrt(17))/(12),x=(3-sqrt(17))/(12)