What are the solutions to the equation x^2+10x+25=16 ?

The solutions to the equation x^2+10x+25=16 are x=-1,x=-9

Find the zeros of x^2+10x+25=16

The zeros of x^2+10x+25=16 are x=-1,x=-9

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x^{2} + 10 x + 25 = 16

x = - 1, x = - 9

Solution steps

x^{2} + 10 x + 25 = 16

Move

16

to the left side

x^{2} + 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 9 = 8

x_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 8}{2 \cdot 1}, x_{2} = \frac{- 10 - 8}{2 \cdot 1}

x = \frac{- 10 + 8}{2 \cdot 1} : - 1

x = \frac{- 10 - 8}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 1, x = - 9

\frac{8 - 2 i}{- 4 + i}

- 7 = - 6 x + 7 x - 7

(5 + 3) (2 - 3)

2 y^{2} - 3 y - 5

2 + 3 (x + 2 x) = - 2 x (2 - 4) + 1

What are the solutions to the equation x^2+10x+25=16 ?
The solutions to the equation x^2+10x+25=16 are x=-1,x=-9
Find the zeros of x^2+10x+25=16
The zeros of x^2+10x+25=16 are x=-1,x=-9