What is the answer to (x+3)^3-(3x-1)^2=x^3-4 ?

The answer to (x+3)^3-(3x-1)^2=x^3-4 is x=-10/11

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(x+3)^3-(3x-1)^2=x^3-4

(x + 3)^{3} - (3 x - 1)^{2} = x^{3} - 4

x = - \frac{10}{11}

Decimal Notation

x = - 0.90909 \dots

Solution steps

(x + 3)^{3} - (3 x - 1)^{2} = x^{3} - 4

Expand

(x + 3)^{3} - (3 x - 1)^{2} : x^{3} + 33 x + 26

x^{3} + 33 x + 26 = x^{3} - 4

Move

26

to the right side

x^{3} + 33 x = x^{3} - 30

Move

x^{3}

to the left side

33 x = - 30

Divide both sides by

33

x = - \frac{10}{11}

(5 - 3) (5 + 3)

6^{- (2)}

4 z^{3} + 8 z^{2} - 9 z - 18

16 t - 0.8 t^{2} = 40

- 17 > - 7 x - 45

What is the answer to (x+3)^3-(3x-1)^2=x^3-4 ?
The answer to (x+3)^3-(3x-1)^2=x^3-4 is x=-10/11
Solve for x: (x+3)^3-(3x-1)^2=x^3-4
The solution is x=-10/11