What are the solutions to the equation (2x-7)^2+8=0 ?

The solutions to the equation (2x-7)^2+8=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i

Find the zeros of (2x-7)^2+8=0

The zeros of (2x-7)^2+8=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i

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(2 x - 7)^{2} + 8 = 0

x = \frac{7}{2} + 2 i, x = \frac{7}{2} - 2 i

Solution steps

(2 x - 7)^{2} + 8 = 0

Move

8

to the right side

(2 x - 7)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 7 = - 8 : x = \frac{7}{2} + 2 i

Solve

2 x - 7 = - - 8 : x = \frac{7}{2} - 2 i

The solutions to the quadratic equation are:

x = \frac{7}{2} + 2 i, x = \frac{7}{2} - 2 i

x^{2} - 12 x + 27 < 0

(\frac{1}{6})^{\frac{1}{6}}

\frac{2}{3 + i}

6 n^{2} + 20 n \leq n^{3}

133 1^{- \frac{1}{3}}

What are the solutions to the equation (2x-7)^2+8=0 ?
The solutions to the equation (2x-7)^2+8=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i
Find the zeros of (2x-7)^2+8=0
The zeros of (2x-7)^2+8=0 are x= 7/2+sqrt(2)i,x= 7/2-sqrt(2)i