What are the solutions to the equation -4k^2-8k-3=-3-5k^2 ?

The solutions to the equation -4k^2-8k-3=-3-5k^2 are k=8,k=0

Find the zeros of -4k^2-8k-3=-3-5k^2

The zeros of -4k^2-8k-3=-3-5k^2 are k=8,k=0

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- 4 k^{2} - 8 k - 3 = - 3 - 5 k^{2}

k = 8, k = 0

Solution steps

- 4 k^{2} - 8 k - 3 = - 3 - 5 k^{2}

Move

5 k^{2}

to the left side

k^{2} - 8 k - 3 = - 3

Move

3

to the left side

k^{2} - 8 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 0 = 8

k_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 1}, k_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 1}

k = \frac{- ( - 8 ) + 8}{2 \cdot 1} : 8

k = \frac{- ( - 8 ) - 8}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 8, k = 0

2 - y = 3 - 2 y

- 6 g + 3 g + 12 > - 18

f (k) = \frac{9 k ^{2} - 33 k + 10}{18 k ^{3} - 200 k}

3 x - 6 = 18

12 - (1 + 1)

What are the solutions to the equation -4k^2-8k-3=-3-5k^2 ?
The solutions to the equation -4k^2-8k-3=-3-5k^2 are k=8,k=0
Find the zeros of -4k^2-8k-3=-3-5k^2
The zeros of -4k^2-8k-3=-3-5k^2 are k=8,k=0