What is 1/(x+1)+1/(x+2)<= 0 ?

The solution to 1/(x+1)+1/(x+2)<= 0 is x<-2\lor-3/2 <= x<-1

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1/(x+1)+1/(x+2)<= 0

\frac{1}{x + 1} + \frac{1}{x + 2} \leq 0

x < - 2 or - \frac{3}{2} \leq x < - 1

Interval Notation

(- \infty, - 2) \cup [- \frac{3}{2}, - 1)

Decimal Notation

x < - 2 or - 1.5 \leq x < - 1

Solution steps

\frac{1}{x + 1} + \frac{1}{x + 2} \leq 0

Rewrite in standard form

\frac{2 x + 3}{( x + 1 ) ( x + 2 )} \leq 0

Identify the intervals

x < - 2 or - \frac{3}{2} \leq x < - 1

x - 1 = 2 x

2^{3} \cdot 2^{5}

\frac{t}{t ^{2}}

(2 + 3)^{2}

4 x^{2} - 35 x + 49

What is 1/(x+1)+1/(x+2)<= 0 ?
The solution to 1/(x+1)+1/(x+2)<= 0 is x<-2\lor-3/2 <= x<-1