What are the solutions to the equation 3x^2+10x-5=0 ?

The solutions to the equation 3x^2+10x-5=0 are x=(-5+2sqrt(10))/3 ,x=-(5+2sqrt(10))/3

Find the zeros of 3x^2+10x-5=0

The zeros of 3x^2+10x-5=0 are x=(-5+2sqrt(10))/3 ,x=-(5+2sqrt(10))/3

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3 x^{2} + 10 x - 5 = 0

x = \frac{- 5 + 2 10}{3}, x = - \frac{5 + 2 10}{3}

Decimal Notation

x = 0.44151 \dots, x = - 3.77485 \dots

Solution steps

3 x^{2} + 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 5) = 410

x_{1, 2} = \frac{- 10 \pm 4 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 4 10}{2 \cdot 3}, x_{2} = \frac{- 10 - 4 10}{2 \cdot 3}

x = \frac{- 10 + 4 10}{2 \cdot 3} : \frac{- 5 + 2 10}{3}

x = \frac{- 10 - 4 10}{2 \cdot 3} : - \frac{5 + 2 10}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 10}{3}, x = - \frac{5 + 2 10}{3}

1 0^{5 b + 2} < 1000

7 x^{2} + 36 x + 5

- x^{3} + 12 x - 44 x + 48

- x^{2} + 4 x + 12

64 - 81 x^{2}

What are the solutions to the equation 3x^2+10x-5=0 ?
The solutions to the equation 3x^2+10x-5=0 are x=(-5+2sqrt(10))/3 ,x=-(5+2sqrt(10))/3
Find the zeros of 3x^2+10x-5=0
The zeros of 3x^2+10x-5=0 are x=(-5+2sqrt(10))/3 ,x=-(5+2sqrt(10))/3