-3x+7<= 19

Solution

- 3 x + 7 \leq 19

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

- 3 x + 7 \leq 19

Move

7

to the right side

- 3 x \leq 12

Multiply both sides by

- 1

3 x \geq - 12

Divide both sides by

3

x \geq - 4

\frac{x ^{2} y - 3 x y ^{2} + 6 x ^{2} y + x y}{x y}

4 n (3 n^{2} + n - 4) - n (3 - n)

\frac{c + 2}{c - 5} - \frac{c}{c + 1}

y^{2} - 5 y + 3 = 17

∣ 2 x + 3 ∣ + 1 < 11