What is factor 2x^3+3x^2-3x-2 ?

The solution to factor 2x^3+3x^2-3x-2 is (x-1)(2x+1)(x+2)

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factor 2x^3+3x^2-3x-2

factor

2 x^{3} + 3 x^{2} - 3 x - 2

(x - 1) (2 x + 1) (x + 2)

Solution steps

2 x^{3} + 3 x^{2} - 3 x - 2

Use the rational root theorem

= (x - 1) \frac{2 x ^{3} + 3 x ^{2} - 3 x - 2}{x - 1}

\frac{2 x ^{3} + 3 x ^{2} - 3 x - 2}{x - 1} = 2 x^{2} + 5 x + 2

= (x - 1) (2 x^{2} + 5 x + 2)

Factor

2 x^{2} + 5 x + 2 : (2 x + 1) (x + 2)

= (x - 1) (2 x + 1) (x + 2)

2^{12}

3 x y + 12 x - 2 y - 8

- 4 x^{2} + 12 x - 9

21 x^{2} - 22 x y + 5 y^{2}

\frac{3 z}{2} + \frac{1}{4} = \frac{7}{8}

What is factor 2x^3+3x^2-3x-2 ?
The solution to factor 2x^3+3x^2-3x-2 is (x-1)(2x+1)(x+2)