What are the solutions to the equation 10r^2+7=-113 ?

The solutions to the equation 10r^2+7=-113 are r=2sqrt(3)i,r=-2sqrt(3)i

Find the zeros of 10r^2+7=-113

The zeros of 10r^2+7=-113 are r=2sqrt(3)i,r=-2sqrt(3)i

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10 r^{2} + 7 = - 113

r = 23 i, r = - 23 i

Solution steps

10 r^{2} + 7 = - 113

Move

7

to the right side

10 r^{2} = - 120

Divide both sides by

10

r^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 12, r = - - 12

- 12 = 23 i

- - 12 = - 23 i

r = 23 i, r = - 23 i

(x^{3}) (4 x^{5})

4 X = 10

0.73 (7)^{2} + 15.8 (7) + 2.7

x^{2} + 29 x - 30

What are the solutions to the equation 10r^2+7=-113 ?
The solutions to the equation 10r^2+7=-113 are r=2sqrt(3)i,r=-2sqrt(3)i
Find the zeros of 10r^2+7=-113
The zeros of 10r^2+7=-113 are r=2sqrt(3)i,r=-2sqrt(3)i