What is 22/8 <(y+7)/4 < 27/8 ?

The solution to 22/8 <(y+7)/4 < 27/8 is 4<y< 13/2

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22/8 <(y+7)/4 < 27/8

\frac{22}{8} < \frac{y + 7}{4} < \frac{27}{8}

4 < y < \frac{13}{2}

Interval Notation

(4, \frac{13}{2})

Decimal Notation

4 < y < 6.5

Solution steps

\frac{22}{8} < \frac{y + 7}{4} < \frac{27}{8}

a < u < b

then

a < u and u < b

\frac{22}{8} < \frac{y + 7}{4} and \frac{y + 7}{4} < \frac{27}{8}

\frac{22}{8} < \frac{y + 7}{4} : y > 4

\frac{y + 7}{4} < \frac{27}{8} : y < \frac{13}{2}

Combine the intervals

y > 4 and y < \frac{13}{2}

Merge Overlapping Intervals

4 < y < \frac{13}{2}

10 d^{2} - 6 d + 35 d - 21

7 > 2 x - 3

\frac{1}{9} + \frac{1}{6}

3 x^{2} - 48 = 0

lo g_{10} (1) = x

What is 22/8 <(y+7)/4 < 27/8 ?
The solution to 22/8 <(y+7)/4 < 27/8 is 4<y< 13/2