What are the solutions to the equation x^2+3x-8=0 ?

The solutions to the equation x^2+3x-8=0 are x=(-3+sqrt(41))/2 ,x=(-3-sqrt(41))/2

Find the zeros of x^2+3x-8=0

The zeros of x^2+3x-8=0 are x=(-3+sqrt(41))/2 ,x=(-3-sqrt(41))/2

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x^{2} + 3 x - 8 = 0

x = \frac{- 3 + 41}{2}, x = \frac{- 3 - 41}{2}

Decimal Notation

x = 1.70156 \dots, x = - 4.70156 \dots

Solution steps

x^{2} + 3 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 8) = 41

x_{1, 2} = \frac{- 3 \pm 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 41}{2 \cdot 1}, x_{2} = \frac{- 3 - 41}{2 \cdot 1}

x = \frac{- 3 + 41}{2 \cdot 1} : \frac{- 3 + 41}{2}

x = \frac{- 3 - 41}{2 \cdot 1} : \frac{- 3 - 41}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 41}{2}, x = \frac{- 3 - 41}{2}

\frac{( 4 h + 6 )}{5} - \frac{( 4 - 4 h )}{3} = \frac{7}{5}

2 x^{2} - 5 x + 67 = 0

- 4 m^{2} + 25 p^{2} x^{2}

4 n^{2} - 96 n - 100

7 x^{2} - 37 x - 30

What are the solutions to the equation x^2+3x-8=0 ?
The solutions to the equation x^2+3x-8=0 are x=(-3+sqrt(41))/2 ,x=(-3-sqrt(41))/2
Find the zeros of x^2+3x-8=0
The zeros of x^2+3x-8=0 are x=(-3+sqrt(41))/2 ,x=(-3-sqrt(41))/2