What are the solutions to the equation 6u^2-24u=0 ?

The solutions to the equation 6u^2-24u=0 are u=4,u=0

Find the zeros of 6u^2-24u=0

The zeros of 6u^2-24u=0 are u=4,u=0

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6 u^{2} - 24 u = 0

u = 4, u = 0

Solution steps

6 u^{2} - 24 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 24)^{2} - 4 \cdot 6 \cdot 0 = 24

u_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 \cdot 6}

Separate the solutions

u_{1} = \frac{- ( - 24 ) + 24}{2 \cdot 6}, u_{2} = \frac{- ( - 24 ) - 24}{2 \cdot 6}

u = \frac{- ( - 24 ) + 24}{2 \cdot 6} : 4

u = \frac{- ( - 24 ) - 24}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

u = 4, u = 0

4 x^{2} - 4 x - 35

∣ 2 x + 7 ∣ < 9

\frac{67500000}{36.1}

- 56 \leq - 8 x

\frac{3 a x y}{6 a y ^{3}}

What are the solutions to the equation 6u^2-24u=0 ?
The solutions to the equation 6u^2-24u=0 are u=4,u=0
Find the zeros of 6u^2-24u=0
The zeros of 6u^2-24u=0 are u=4,u=0