What are the solutions to the equation (h+6)(h-7)=0 ?

The solutions to the equation (h+6)(h-7)=0 are h=-6,h=7

Find the zeros of (h+6)(h-7)=0

The zeros of (h+6)(h-7)=0 are h=-6,h=7

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(h + 6) (h - 7) = 0

h = - 6, h = 7

Solution steps

(h + 6) (h - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

h + 6 = 0 or h - 7 = 0

Solve

h + 6 = 0 : h = - 6

Solve

h - 7 = 0 : h = 7

The solutions to the quadratic equation are:

h = - 6, h = 7

6 a^{2} - 8 a - 30

- (2 x - 1) = - 5 (2 x + 9)

3 (2 x + 2) - x - 2 = 39

\frac{x}{4} - 2 \geq 6

What are the solutions to the equation (h+6)(h-7)=0 ?
The solutions to the equation (h+6)(h-7)=0 are h=-6,h=7
Find the zeros of (h+6)(h-7)=0
The zeros of (h+6)(h-7)=0 are h=-6,h=7