What is e^{-3}+(3e^{-3})/2+(9e^{-3})/2 ?

The solution to e^{-3}+(3e^{-3})/2+(9e^{-3})/2 is 7/(e^3)

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simplify e^{-3}+(3e^{-3})/2+(9e^{-3})/2

simplify

e^{- 3} + \frac{3 e ^{- 3}}{2} + \frac{9 e ^{- 3}}{2}

\frac{7}{e ^{3}}

Decimal Notation

0.34850 \dots

Solution steps

e^{- 3} + \frac{3 e ^{- 3}}{2} + \frac{9 e ^{- 3}}{2}

Combine the fractions

\frac{3 e ^{- 3}}{2} + \frac{9 e ^{- 3}}{2} : \frac{6}{e ^{3}}

= e^{- 3} + \frac{6}{e ^{3}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3}} + \frac{6}{e ^{3}}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 6}{e ^{3}}

Add the numbers:

1 + 6 = 7

= \frac{7}{e ^{3}}

25 x^{4} - 36 y^{2}

\frac{3}{2 2}

- x^{2} = 2

1 \geq 2

\frac{7 x}{x + 1} \leq \frac{6 x + 3}{4}

What is e^{-3}+(3e^{-3})/2+(9e^{-3})/2 ?
The solution to e^{-3}+(3e^{-3})/2+(9e^{-3})/2 is 7/(e^3)