What is the answer to x/2+(x-1)/3-(x+1)/4 =1 ?

The answer to x/2+(x-1)/3-(x+1)/4 =1 is x= 19/7

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x/2+(x-1)/3-(x+1)/4 =1

\frac{x}{2} + \frac{x - 1}{3} - \frac{x + 1}{4} = 1

x = \frac{19}{7}

Decimal Notation

x = 2.71428 \dots

Solution steps

\frac{x}{2} + \frac{x - 1}{3} - \frac{x + 1}{4} = 1

Multiply by LCM

6 x + 4 (x - 1) - 3 (x + 1) = 12

Expand

6 x + 4 (x - 1) - 3 (x + 1) : 7 x - 7

7 x - 7 = 12

Move

7

to the right side

7 x = 19

Divide both sides by

7

x = \frac{19}{7}

\frac{( x ^{2} - 27 )}{( a ^{3} - 1 )}

\frac{2 a}{9 - a ^{2}} \cdot \frac{a - 3}{a ^{3} + a}

6 a - 3 > 21

\frac{5}{6} x - 4 = - 2

4 y - 1 = 3 (- 5 - y)

What is the answer to x/2+(x-1)/3-(x+1)/4 =1 ?
The answer to x/2+(x-1)/3-(x+1)/4 =1 is x= 19/7
Solve for x: x/2+(x-1)/3-(x+1)/4 =1
The solution is x= 19/7