What are the solutions to the equation x^2= 3/4 ?

The solutions to the equation x^2= 3/4 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2

Find the zeros of x^2= 3/4

The zeros of x^2= 3/4 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2

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x^{2} = \frac{3}{4}

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 0.86602 \dots, x = - 0.86602 \dots

Solution steps

x^{2} = \frac{3}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{4}, x = - \frac{3}{4}

\frac{3}{4} = \frac{3}{2}

- \frac{3}{4} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

\frac{3 ( x + 4 )}{2} + 1 = - 7

\frac{n}{9} = 6 \cdot 7

27 x^{3} - 9 x^{2} + 15 x

0.36 y = 18

- 4 n = 22

What are the solutions to the equation x^2= 3/4 ?
The solutions to the equation x^2= 3/4 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2
Find the zeros of x^2= 3/4
The zeros of x^2= 3/4 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2