What is ((-2+i)(1+3i))/(-1+2i)-2i ?

The solution to ((-2+i)(1+3i))/(-1+2i)-2i is -1+i

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simplify ((-2+i)(1+3i))/(-1+2i)-2i

simplify

\frac{( - 2 + i ) ( 1 + 3 i )}{- 1 + 2 i} - 2 i

- 1 + i

Solution steps

\frac{( - 2 + i ) ( 1 + 3 i )}{- 1 + 2 i} - 2 i

Simplify

\frac{( - 2 + i ) ( 1 + 3 i )}{- 1 + 2 i} : \frac{- 5 + 15 i}{5}

= \frac{- 5 + 15 i}{5} - 2 i

Cancel

\frac{- 5 + 15 i}{5} : - 1 + 3 i

= - 1 + 3 i - 2 i

Add similar elements:

3 i - 2 i = i

= - 1 + i

62 \cdot 2

x^{4} + 2 x^{3} - 3 x^{2} - 25 x^{2} - 50 x + 75

\frac{9}{8} + \frac{3}{2}

2 x^{3} - 8 x^{2} - 24 x

2 a^{2} + 12 a = - 32

What is ((-2+i)(1+3i))/(-1+2i)-2i ?
The solution to ((-2+i)(1+3i))/(-1+2i)-2i is -1+i