What are the solutions to the equation -7x^2+63=0 ?

The solutions to the equation -7x^2+63=0 are x=3,x=-3

Find the zeros of -7x^2+63=0

The zeros of -7x^2+63=0 are x=3,x=-3

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- 7 x^{2} + 63 = 0

x = 3, x = - 3

Solution steps

- 7 x^{2} + 63 = 0

Move

63

to the right side

- 7 x^{2} = - 63

Divide both sides by

- 7

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

∣ 7 - 4 x ∣ \leq 9

- 2 (- 3 u - 10) + 1 = 15

- 8 + 8 g = 56

9 y + 2 (2 y - 13) = 4 (5 + y) + 5 (1 + y) + 1

6 p^{2} = - 2 p + 3

What are the solutions to the equation -7x^2+63=0 ?
The solutions to the equation -7x^2+63=0 are x=3,x=-3
Find the zeros of -7x^2+63=0
The zeros of -7x^2+63=0 are x=3,x=-3