What is |((2x-4))/2 |<= 1 ?

The solution to |((2x-4))/2 |<= 1 is 1<= x<= 3

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|((2x-4))/2 |<= 1

\frac{( 2 x - 4 )}{2} \leq 1

1 \leq x \leq 3

Interval Notation

[1, 3]

Solution steps

\frac{2 x - 4}{2} \leq 1

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 1 \leq \frac{2 x - 4}{2} \leq 1

\frac{2 x - 4}{2} \geq - 1 and \frac{2 x - 4}{2} \leq 1

x \geq 1 and x \leq 3

Merge Overlapping Intervals

1 \leq x \leq 3

15 x^{0} y^{- 2}

(x^{\frac{3}{2}})^{2}

c - 12 > - 1

\frac{1}{\frac{1}{16}}

x (5 x + 6) = 8