What are the solutions to the equation x^2-14x-2=0 ?

The solutions to the equation x^2-14x-2=0 are x=7+sqrt(51),x=7-sqrt(51)

Find the zeros of x^2-14x-2=0

The zeros of x^2-14x-2=0 are x=7+sqrt(51),x=7-sqrt(51)

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x^{2} - 14 x - 2 = 0

x = 7 + 51, x = 7 - 51

Decimal Notation

x = 14.14142 \dots, x = - 0.14142 \dots

Solution steps

x^{2} - 14 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 2) = 251

x_{1, 2} = \frac{- ( - 14 ) \pm 2 51}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 51}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 51}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 51}{2 \cdot 1} : 7 + 51

x = \frac{- ( - 14 ) - 2 51}{2 \cdot 1} : 7 - 51

The solutions to the quadratic equation are:

x = 7 + 51, x = 7 - 51

5 x - 7 < 38

- 7 x^{2} + 4 x - 2 = 0

b^{9} - 1

5 (g - 3) > 7 (2 g + 5) - (- 4 g)

What are the solutions to the equation x^2-14x-2=0 ?
The solutions to the equation x^2-14x-2=0 are x=7+sqrt(51),x=7-sqrt(51)
Find the zeros of x^2-14x-2=0
The zeros of x^2-14x-2=0 are x=7+sqrt(51),x=7-sqrt(51)