What is factor 25x^4-81y^2 ?

The solution to factor 25x^4-81y^2 is (5x^2+9y)(5x^2-9y)

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factor 25x^4-81y^2

factor

25 x^{4} - 81 y^{2}

(5 x^{2} + 9 y) (5 x^{2} - 9 y)

Solution steps

25 x^{4} - 81 y^{2}

25 x^{4} = (5 x^{2})^{2}

81 y^{2} = (9 y)^{2}

= (5 x^{2})^{2} - (9 y)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(5 x^{2})^{2} - (9 y)^{2} = (5 x^{2} + 9 y) (5 x^{2} - 9 y)

= (5 x^{2} + 9 y) (5 x^{2} - 9 y)

\frac{6}{5} x - \frac{1}{3} > 2 x + 3

x^{3} y - 25 x y^{3}

\frac{x ^{2} - 2 x - 5}{x ^{2} + 4 x - 7} < 1

c^{2} + 6 c + 9

4 (x - 7)^{2} + 20 = 24

What is factor 25x^4-81y^2 ?
The solution to factor 25x^4-81y^2 is (5x^2+9y)(5x^2-9y)