What are the solutions to the equation 10x^2+9x-9=0 ?

The solutions to the equation 10x^2+9x-9=0 are x= 3/5 ,x=-3/2

Find the zeros of 10x^2+9x-9=0

The zeros of 10x^2+9x-9=0 are x= 3/5 ,x=-3/2

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10 x^{2} + 9 x - 9 = 0

x = \frac{3}{5}, x = - \frac{3}{2}

Decimal Notation

x = 0.6, x = - 1.5

Solution steps

10 x^{2} + 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 10 ( - 9 )}{2 \cdot 10}

9^{2} - 4 \cdot 10 (- 9) = 21

x_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 9 + 21}{2 \cdot 10}, x_{2} = \frac{- 9 - 21}{2 \cdot 10}

x = \frac{- 9 + 21}{2 \cdot 10} : \frac{3}{5}

x = \frac{- 9 - 21}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - \frac{3}{2}

3 (x - 4) = 0 - 2 x + 7

2 d - 5 < 1 or - 3 d - 2 > 7

\frac{5}{6} - \frac{7}{9}

\frac{8}{- 4 - 2 i}

3 x^{3} - 9 x

What are the solutions to the equation 10x^2+9x-9=0 ?
The solutions to the equation 10x^2+9x-9=0 are x= 3/5 ,x=-3/2
Find the zeros of 10x^2+9x-9=0
The zeros of 10x^2+9x-9=0 are x= 3/5 ,x=-3/2