What are the solutions to the equation 0=-16t^2+105t-34 ?

The solutions to the equation 0=-16t^2+105t-34 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)

Find the zeros of 0=-16t^2+105t-34

The zeros of 0=-16t^2+105t-34 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - 16 t^{2} + 105 t - 34

t = \frac{105 - 8849}{32}, t = \frac{105 + 8849}{32}

Decimal Notation

t = 0.34158 \dots, t = 6.22091 \dots

Solution steps

0 = - 16 t^{2} + 105 t - 34

Switch sides

- 16 t^{2} + 105 t - 34 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 105 \pm 10 5 ^{2} - 4 ( - 16 ) ( - 34 )}{2 ( - 16 )}

10 5^{2} - 4 (- 16) (- 34) = 8849

t_{1, 2} = \frac{- 105 \pm 8849}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 105 + 8849}{2 ( - 16 )}, t_{2} = \frac{- 105 - 8849}{2 ( - 16 )}

t = \frac{- 105 + 8849}{2 ( - 16 )} : \frac{105 - 8849}{32}

t = \frac{- 105 - 8849}{2 ( - 16 )} : \frac{105 + 8849}{32}

The solutions to the quadratic equation are:

t = \frac{105 - 8849}{32}, t = \frac{105 + 8849}{32}

3 x + 5 = 2 (x - 1)

x^{2} - 11

(2 y)^{2}

196 a^{2} - b^{2}

x + 2 < 3 - x

What are the solutions to the equation 0=-16t^2+105t-34 ?
The solutions to the equation 0=-16t^2+105t-34 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)
Find the zeros of 0=-16t^2+105t-34
The zeros of 0=-16t^2+105t-34 are t=(105-sqrt(8849))/(32),t=(105+sqrt(8849))/(32)