What are the solutions to the equation 3^2+b^2=10^2 ?

The solutions to the equation 3^2+b^2=10^2 are b=sqrt(91),b=-sqrt(91)

Find the zeros of 3^2+b^2=10^2

The zeros of 3^2+b^2=10^2 are b=sqrt(91),b=-sqrt(91)

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3^{2} + b^{2} = 1 0^{2}

b = 91, b = - 91

Decimal Notation

b = 9.53939 \dots, b = - 9.53939 \dots

Solution steps

3^{2} + b^{2} = 1 0^{2}

Move

3^{2}

to the right side

b^{2} = 91

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 91, b = - 91

\frac{- 390}{- 65}

18 < 13 + x

\frac{1}{\frac{1}{e}}

\frac{d}{- 3} \leq - 2

What are the solutions to the equation 3^2+b^2=10^2 ?
The solutions to the equation 3^2+b^2=10^2 are b=sqrt(91),b=-sqrt(91)
Find the zeros of 3^2+b^2=10^2
The zeros of 3^2+b^2=10^2 are b=sqrt(91),b=-sqrt(91)