What are the solutions to the equation x^2+2x-224=0 ?

The solutions to the equation x^2+2x-224=0 are x=14,x=-16

Find the zeros of x^2+2x-224=0

The zeros of x^2+2x-224=0 are x=14,x=-16

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x^{2} + 2 x - 224 = 0

x = 14, x = - 16

Solution steps

x^{2} + 2 x - 224 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 224 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 224) = 30

x_{1, 2} = \frac{- 2 \pm 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 30}{2 \cdot 1}, x_{2} = \frac{- 2 - 30}{2 \cdot 1}

x = \frac{- 2 + 30}{2 \cdot 1} : 14

x = \frac{- 2 - 30}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 14, x = - 16

2 a^{3} + 38 a^{2} + 68 a

y - 11 = 13

x^{10} - y^{2}

x + 2 x = 180

\frac{4 a ^{5}}{7 b ^{4}} \cdot \frac{2 b ^{2}}{2 a ^{4}}

What are the solutions to the equation x^2+2x-224=0 ?
The solutions to the equation x^2+2x-224=0 are x=14,x=-16
Find the zeros of x^2+2x-224=0
The zeros of x^2+2x-224=0 are x=14,x=-16