What are the solutions to the equation 4x^2+x-105=0 ?

The solutions to the equation 4x^2+x-105=0 are x=5,x=-21/4

Find the zeros of 4x^2+x-105=0

The zeros of 4x^2+x-105=0 are x=5,x=-21/4

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4 x^{2} + x - 105 = 0

x = 5, x = - \frac{21}{4}

Decimal Notation

x = 5, x = - 5.25

Solution steps

4 x^{2} + x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 105 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 105) = 41

x_{1, 2} = \frac{- 1 \pm 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 41}{2 \cdot 4}, x_{2} = \frac{- 1 - 41}{2 \cdot 4}

x = \frac{- 1 + 41}{2 \cdot 4} : 5

x = \frac{- 1 - 41}{2 \cdot 4} : - \frac{21}{4}

The solutions to the quadratic equation are:

x = 5, x = - \frac{21}{4}

\frac{375 ( 1 - ( \frac{1}{5} ) ^{200} )}{1 - \frac{1}{5}}

4 x^{2} - 20 x + 9 = 0

256 x^{2} - 196 y^{2}

∣ - 4 + p ∣ + 3 = 13

i^{94}

What are the solutions to the equation 4x^2+x-105=0 ?
The solutions to the equation 4x^2+x-105=0 are x=5,x=-21/4
Find the zeros of 4x^2+x-105=0
The zeros of 4x^2+x-105=0 are x=5,x=-21/4