What are the solutions to the equation 4^2+b^2=11^2 ?

The solutions to the equation 4^2+b^2=11^2 are b=sqrt(105),b=-sqrt(105)

Find the zeros of 4^2+b^2=11^2

The zeros of 4^2+b^2=11^2 are b=sqrt(105),b=-sqrt(105)

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4^{2} + b^{2} = 1 1^{2}

b = 105, b = - 105

Decimal Notation

b = 10.24695 \dots, b = - 10.24695 \dots

Solution steps

4^{2} + b^{2} = 1 1^{2}

Move

4^{2}

to the right side

b^{2} = 105

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 105, b = - 105

\frac{2}{3} \times 4

z^{3} + 2 z^{2} - 3 z - 6

\frac{5}{6} x - \frac{1}{3} = - 2

2 x + 3 \leq - 4 or 2 x + 3 \geq 4

\frac{( 2 - 2 x )}{3 x + 5} \leq 0

What are the solutions to the equation 4^2+b^2=11^2 ?
The solutions to the equation 4^2+b^2=11^2 are b=sqrt(105),b=-sqrt(105)
Find the zeros of 4^2+b^2=11^2
The zeros of 4^2+b^2=11^2 are b=sqrt(105),b=-sqrt(105)