What is the answer to x-1-((x-2)/2)+((x-3)/3)=0 ?

The answer to x-1-((x-2)/2)+((x-3)/3)=0 is x= 6/5

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x-1-((x-2)/2)+((x-3)/3)=0

x - 1 - (\frac{x - 2}{2}) + (\frac{x - 3}{3}) = 0

x = \frac{6}{5}

Decimal Notation

x = 1.2

Solution steps

x - 1 - (\frac{x - 2}{2}) + (\frac{x - 3}{3}) = 0

Move

1

to the right side

x - \frac{x - 2}{2} + \frac{x - 3}{3} = 1

Multiply by LCM

6 x - 3 (x - 2) + 2 (x - 3) = 6

Expand

6 x - 3 (x - 2) + 2 (x - 3) : 5 x

5 x = 6

Divide both sides by

5

x = \frac{6}{5}

(2 x + 5) (3 x - 4) = 0

x^{2} - 5 x - 14 \leq 0

5 + 2.5 d \leq 20

\frac{15}{5} = \frac{m}{4}

\frac{4}{x - 3} \leq \frac{2}{x + 5}

What is the answer to x-1-((x-2)/2)+((x-3)/3)=0 ?
The answer to x-1-((x-2)/2)+((x-3)/3)=0 is x= 6/5
Solve for x: x-1-((x-2)/2)+((x-3)/3)=0
The solution is x= 6/5